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Inequality Notes class 8

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  Inequality Notes class 8 What is Inequality? Inequality refers to a mathematical statement that shows the relationship between two expressions that are not equal. In inequalities, the two expressions are connected using inequality symbols. Inequality Symbols: > (Greater Than) : Shows that the value on the left is larger than the value on the right. Example: 5 > 3 5 > 3 < (Less Than) : Shows that the value on the left is smaller than the value on the right. Example: 3 < 5 3 < 5 ≥ (Greater Than or Equal To) : Indicates that the value on the left is either greater than or equal to the value on the right. Example: 5 ≥ 3 5 \geq 3 ≤ (Less Than or Equal To) : Indicates that the value on the left is either less than or equal to the value on the right. Example: 3 ≤ 5 3 \leq 5 ≠ (Not Equal To) : Indicates that two values are not equal. Example: 5 ≠ 3 5 \neq 3 Solving Inequalities: Just like solving equations, inequalities can be solved to find th...
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An object dropped from a leaf false with a constant acceleration of 10 m/s2. Find its Speed 2 second after it was dropped.

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  An object dropped from a leaf false with a constant acceleration of 10 m/s 2 . Find its Speed 2 second after it was dropped.                            Solution: Given: Initial speed, u = 0 u = 0 (object is dropped) Acceleration due to gravity, a = 10   m/s 2 a = 10 \, \text{m/s}^2 Time, t = 2 \, \text{s} t  = 2 s Formula used: v = u + a t Calculation: v = 0 + ( 10 × 2 ) = 20   m/s Answer: The speed of the object after 2 seconds is 20 m/s (downwards) .
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A train travels 20 km at a uniform speed of 60 km/h and the next 20 km at a uniform speed of 80 km/hr. calculate its average speed.

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                                A train travels 20 km at a uniform speed of 60 km/h and the next 20 km at a uniform speed of 80 km/hr. calculate its average speed. Given: First distance d 1 = 20   km d_1 = 20 \, \text{km} , speed v 1 = 60   km/h v_1 = 60 \, \text{km/h} Second distance d 2 = 20   km d_2 = 20 \, \text{km} , speed v 2 = 80   km/h v_2 = 80 \, \text{km/h} Step 1: Time taken for each part t 1 = 20 60 = 1 3  h t_1 = \frac{20}{60} = \frac{1}{3} \text{ h} t 2 = 20 80 = 1 4  h t_2 = \frac{20}{80} = \frac{1}{4} \text{ h} Step 2: Total distance and total time Total distance = 20 + 20 = 40  km \text{Total distance} = 20 + 20 = 40 \text{ km} Total time = 1 3 + 1 4 = 4 + 3 12 = 7 12  h \text{Total time} = \frac{1}{3} + \frac{1}{4} = \frac{4 + 3}{12} = \frac{7}{12} \text{ h} Step 3: Average speed Average speed = Total distance Total time = 40 7 / 12 =...
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A boy is running on a straight road. He runs 500 m towards north in 2 minutes 10 seconds and then turns back and runs 200 m in 1 minute. Calculate i) His average speed and magnitude of average velocity during first 2 minutes 10 seconds and ii) His average speed and magnitude of average velocity during the whole journey.

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    A boy is running on a straight road. He runs 500 m towards north in 2 minutes 10 seconds and then turns back and runs 200 m in 1 minute. Calculate             i) His average speed and magnitude of average velocity during first 2 minutes 10 seconds and             ii) His average speed and magnitude of average velocity during the whole journey. Solution: Given: Distance covered towards north  = 500 m Time taken = 2 minutes 10 seconds = 130 s Then he runs back 200 m in 1 minute = 60 s (i) First 2 minutes 10 seconds This is only the first part of the motion. Distance covered = 500 m Time taken = 130 s (a) Average Speed :- Average Speed = Total Distance / Total Time = 500 / 130 = 3.85 m/s (b) Magnitude of Average Velocity :-      Displacement = 500 m towards north       Average velocity = Displacement / Time = 500 / 130 = 3.85 m/s (ii) Whole journey Total distance covered = 5...
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A taxi driver noted the reading on the odometer fitted in the vehicle as 1052 km when he started the journey. After 30 minutes drive, he noted that the odometer reading was 1088 km. find the average speed of the taxi.

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                                   A taxi driver noted the reading on the odometer fitted in the vehicle as 1052 km when he started the journey. After 30 minutes drive, he noted that the odometer reading was 1088 km. find the average speed of the taxi. Solution: Given: Initial odometer reading = 1052 km Final odometer reading = 1088 km Time taken = 30 minutes = 0.5 hour Distance travelled: 1088 − 1052 = 36  km 1088 - 1052 = 36 \text{ km} Average speed: Average speed = Distance Time = 36 0.5 = 72  km/h \text{Average speed} = \frac{\text{Distance}}{\text{Time}} = \frac{36}{0.5} = 72 \text{ km/h} Average speed of the taxi = 72 km/h
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Heredity class 10 important MCQ

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  Heredity – Important MCQs (Class 10) 1–20: Basics of Heredity The transmission of traits from parents to offspring is called A) Variation B) Evolution C) Heredity D) Adaptation Ans: C The scientific study of heredity is known as A) Ecology B) Genetics C) Taxonomy D) Embryology Ans: B Who is known as the Father of Genetics? A) Darwin B) Lamarck C) Mendel D) Morgan Ans: C Mendel conducted experiments on A) Pea plant B) Wheat C) Rice D) Maize Ans: A The alternative forms of a gene are called A) Chromosomes B) Alleles C) Traits D) DNA Ans: B The gene controlling a single trait is called A) Polygenic B) Monogenic C) Digenic D) Multigenic Ans: B A dominant trait is expressed when A) Present only in homozygous condition B) Present in heterozygous condition...
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A wave moves a distance of 8 m in 0.05 s. Find the velocity of the wave.

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 Numerical: A wave moves a distance of 8 m in 0.05 s. Find the velocity of the wave. Solution: Given: Distance d  =  8   m Time t  =  0.05   s Velocity of the wave is given by: v = d t v = \frac{d}{t} ​ v = 8 0.05 = 160   m/s v = \frac{8}{0.05} = 160 \,\text{m/s} Velocity of the wave = 160 m/s
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