A body moves with an initial velocity of 2 m/s and uniform acceleration of 3 m/s2. Calculate the velocity when it has traveled a distance of 77 m.

 A body moves with an initial velocity of 2 m/s and uniform acceleration of 3 m/s². Calculate the velocity when it has traveled a distance of 77 m.

Solution:

Given:

• Initial velocity (u) = 2 m/s
• Acceleration (a) = 3 m/s²
• Displacement (s) = 77 m

Since time is not given, we use the third equation of motion:

$$v^2=u^2+2as$$

Step 1: Substitute values

$$v^2 = (2)^2 + 2(3)(77)$$
$$v^2 = 4 + 6 × 77$$
$$v^2 = 4 + 462$$
$$v^2 = 466$$

Step 2: Take square root

$$v = \sqrt{466}$$ $$v\approx 21.56\text{ m/s}$$

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